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TMUA 2020 · Paper 1 · Question 7
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Given that
2
3
x
=
8
(
y
+
3
)
and
4
(
x
+
1
)
=
8
(
y
+
3
)
1
6
(
y
+
1
)
what is the value of
x
+
y
?
A
−
23
B
−
22
C
−
15
D
−
14
E
−
11
F
−
10
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