Edexcel Mathematics June 2018 · Paper 1 · Question 5 · ExamRizz

ExamRizzEdexcel MathematicsMathematics

June 2018 · Paper 1 · Question 5 · 5 marks

5. Given that 3sin 3 θ π π 3sin 3 θ π π y θ y θ θ θ= − θ θ= − < < < < 2sin 2cos 4 4 2sin 2cos 4 4 + + show that d 3 y A π π θ d 3 y A π π θ θ θ= − d 1 sin 2 4 4 d 1 sin 2 4 4 + θ θ= − < < < < + where A is a rational constant to be found.