Diffraction
Single-slit patterns, diffraction gratings, and the equation d sin θ = nλ
SPEC 3.3.2.2 • WAVES
What is Diffraction?
Definition
Diffraction is the spreading of waves when they pass through a gap or around an obstacle.
Diffraction occurs with all types of waves, including light, sound, and water waves. The effect is most noticeable when:
Key Condition
Diffraction is most significant when the gap width is comparable to the wavelength of the wave.
Gap width ≈ λ → Maximum diffraction
Plane waves spread out after passing through a narrow gap
Exam Tip
The wavelength is unaffected during diffraction. Only the direction of wave propagation changes - the wave spreads out, but its wavelength remains the same.
Factors Affecting Diffraction
The amount of spreading depends on the relationship between gap width and wavelength:
Key Rule
Diffraction increases when: (1) gap width decreases, or (2) wavelength increases
Maximum diffraction occurs when gap width ≈ wavelength
Single-Slit Diffraction
When monochromatic laser light passes through a narrow single slit, a distinctive diffraction pattern is observed on a screen:
Pattern Features
Central maximum: Bright, wide band in the middle
Secondary maxima: Dimmer bands either side
Minima: Dark regions between bright bands
Central maximum is twice as wide as secondary maxima
Single-Slit Pattern
Intensity vs angle for single-slit diffraction
Bright Fringes
Caused by constructive interference between wavelets from different parts of the slit
Dark Fringes
Caused by destructive interference - wavelets cancel out completely
Remember
The intensity of secondary maxima decreases rapidly as you move away from the centre. The central maximum is much brighter and wider than the others.
Effect of Slit Width
The width of the central maximum depends on the slit width:
Key Relationship
Narrower slit → Wider central maximum
This is because a narrower slit causes more diffraction (greater spreading of the waves).
Common Mistake
Students often think a narrower slit gives a narrower pattern - it's the opposite! More diffraction = more spreading.
Effect of Wavelength
The width of the central maximum also depends on the wavelength of light used:
Key Relationship
Longer wavelength → Wider central maximum
Red light (λ ≈ 700 nm) diffracts more than blue light (λ ≈ 450 nm).
Factor ChangedEffect on Central Maximum Width
Slit width decreasedWidth increases (more spreading)
Wavelength increasedWidth increases (more spreading)
Screen distance increasedWidth increases (pattern magnified)
White Light Diffraction
When white light passes through a single slit, each wavelength diffracts by a different amount:
White light single-slit diffraction pattern
Pattern Features
Central fringe: White (all colours overlap at centre)
Outer fringes: Coloured spectra
Violet: Closest to centre (shortest λ, least diffraction)
Red: Furthest from centre (longest λ, most diffraction)
Worked Example01
A laser beam passes through a single slit. The slit width is halved. Describe and explain the change to the diffraction pattern.
1
The central maximum becomes wider.
2
Explanation: A narrower slit causes more diffraction (greater spreading of the waves).
3
The intensity of the central maximum decreases.
4
Explanation: The same amount of light energy is spread over a larger area.
Key point: Narrower slit → wider pattern, lower intensity
Diffraction Gratings
Definition
A diffraction grating consists of many equally-spaced parallel slits. Light diffracts through each slit and the diffracted beams interfere.
Grating Specification
Gratings are specified by the number of lines per millimetre (e.g., 300 lines/mm).
The slit spacing (distance between adjacent slits) is:where N = number of lines per metre
Grating vs Double Slit
A diffraction grating produces a pattern similar to Young's double slit, but with important differences:
FeatureDouble SlitDiffraction Grating
MaximaBroad, diffuseSharp, narrow lines
IntensityLowerHigher (more slits contributing)
MeasurementHarder to measure accuratelyEasier to measure precisely
Why Sharper?
More slits means more beams interfering. Constructive interference only occurs at very specific angles, making the maxima narrower and brighter.
Deriving the Grating Equation
You need to know how to derive the diffraction grating equation:
Step 1: Coherent Sources
Light enters the grating as parallel rays. It diffracts through each slit. The slits act as coherent sources (in phase, same wavelength). These diffracted waves interfere with each other.
Step 2: First Order Maximum
The 1st order maximum occurs at an angle where the path difference between adjacent slits equals one wavelength λ (for constructive interference). Call this angle θ.
Step 3: Create Triangle
We know: the distance between slits is d, the path difference is λ, and the angle is θ.
Grating Equation Derivation
Step 4: Use Trigonometry
From the triangle, using trigonometry:
Step 5: Generalise for All Orders
Maxima occur when path difference = whole number of wavelengths (nλ). Therefore:
Grating Equation
d = slit spacing (m)
θ = angle of diffraction from normal
n = order number (0, 1, 2, 3...)
λ = wavelength (m)
Understanding Orders
n = 0: Zero order (straight through, θ = 0°)
n = 1: First order maxima (one each side)
n = 2: Second order maxima, etc.
Maximum Visible Order
Since sin θ cannot exceed 1, there is a maximum order that can be observed:
Maximum Order
From , the maximum occurs when (i.e., θ = 90°)Take the integer part (round down)
Example
If d = 2.0 μm and λ = 600 nm:
Maximum order = 3 (take integer part)
Orders visible: n = 0, 1, 2, 3 (on each side)
Total Maxima
Total number of maxima = 2n_max + 1
(n_max on each side, plus the zero order in the middle)
Common Mistake
Don't forget that diffraction occurs on both sides of the central axis. Each order (n = 1, 2, 3...) appears twice - once on each side of the zero order.
Worked Example02
A diffraction grating has 500 lines per mm. Monochromatic light of wavelength 589 nm is incident normally on the grating. Calculate the angle of the first-order maximum.
1
Calculate slit spacing: d = 1/(500 × 10³) = 2.0 × 10⁻⁶ m
2
Use grating equation: d sin θ = nλ
3
For n = 1: sin θ = λ/d = (589 × 10⁻⁹)/(2.0 × 10⁻⁶)
4
sin θ = 0.2945
5
θ = sin⁻¹(0.2945) = 17.1°
Answer: θ = 17.1°
Worked Example03
A grating with 300 lines per mm is used with light of wavelength 650 nm. Calculate (a) the maximum order visible, and (b) the total number of maxima observed.
1
Calculate slit spacing: d = 1/(300 × 10³) = 3.33 × 10⁻⁶ m
2
Part (a): n_max = d/λ = (3.33 × 10⁻⁶)/(650 × 10⁻⁹) = 5.13
3
Maximum order = 5 (integer part)
4
Part (b): Total maxima = 2n_max + 1 = 2(5) + 1 = 11
Answer: (a) 5, (b) 11 maxima
Worked Example04
Light passes through a diffraction grating with 600 lines per mm. The second-order maximum is observed at an angle of 43.2°. Calculate the wavelength of the light.
1
Calculate slit spacing: d = 1/(600 × 10³) = 1.67 × 10⁻⁶ m
2
Rearrange grating equation: λ = d sin θ / n
3
λ = (1.67 × 10⁻⁶ × sin 43.2°) / 2
4
λ = (1.67 × 10⁻⁶ × 0.684) / 2 = 5.71 × 10⁻⁷ m
Answer: λ = 571 nm
Worked Example05
A grating produces a first-order maximum at 15.0° for red light (λ = 650 nm) and at 11.5° for blue light (λ = 480 nm). Verify these results are consistent with the same grating.
1
For red light: d = nλ/sin θ = (1 × 650 × 10⁻⁹)/sin 15.0°
2
d = (650 × 10⁻⁹)/0.259 = 2.51 × 10⁻⁶ m
3
For blue light: d = (1 × 480 × 10⁻⁹)/sin 11.5°
4
d = (480 × 10⁻⁹)/0.199 = 2.41 × 10⁻⁶ m
5
The values are close (within ~4%), confirming same grating (small difference due to measurement uncertainty)
Answer: Yes, consistent (d ≈ 2.5 μm)
Applications of Diffraction Gratings
Analysing Light (Spectroscopy)
Diffraction gratings separate wavelengths in light from different substances. The wavelengths present reveal information about the substance - used to analyse starlight and identify elements.
Wavelength Measurement
Precisely measuring wavelengths of light sources by measuring diffraction angles. More accurate than prisms.
X-ray Crystallography
Atoms in crystals act like diffraction gratings. X-rays diffract through the gaps between atoms. By analysing the diffraction pattern, we can determine atomic spacing in the crystal structure.
CD/DVD Surfaces
The tracks on CDs and DVDs act as reflection gratings, creating rainbow patterns when white light is reflected.
Why Gratings Over Prisms?
More accurate wavelength measurement
Linear dispersion (angles proportional to wavelength)
Can separate very close wavelengths (high resolution)
Practice
Question 1: A diffraction grating has 400 lines per mm. Light of wavelength 550 nm is incident normally. Calculate the angle of the second-order maximum.
1
d = 1/(400 × 10³) = 2.5 × 10⁻⁶ m
2
sin θ = nλ/d = (2 × 550 × 10⁻⁹)/(2.5 × 10⁻⁶) = 0.44
3
θ = sin⁻¹(0.44) = 26.1°
Practice
Question 2: A grating produces a third-order maximum at 62.5° for monochromatic light. The slit spacing is 1.80 μm. Calculate the wavelength of the light.
1
λ = d sin θ / n
2
λ = (1.80 × 10⁻⁶ × sin 62.5°) / 3
3
λ = (1.80 × 10⁻⁶ × 0.887) / 3 = 5.32 × 10⁻⁷ m
4
λ = 532 nm (green light)
Practice
Question 3: A grating with 750 lines per mm is illuminated with light of wavelength 620 nm. How many complete orders can be observed on one side of the central maximum?
1
d = 1/(750 × 10³) = 1.33 × 10⁻⁶ m
2
n_max = d/λ = (1.33 × 10⁻⁶)/(620 × 10⁻⁹) = 2.15
3
Maximum order = 2 (take integer part)
4
Orders visible on one side: n = 1, 2
Summary
Key Equations
EquationDescription
d sin θ = nλDiffraction grating equation
d = 1/NSlit spacing (N = lines per metre)
n_max = d/λMaximum order (integer part)
Key Concepts
Single slit: Narrower slit or longer λ → wider central maximum
White light: Central white fringe, coloured spectra outside
Grating: Produces sharp, bright maxima at specific angles
Orders: n = 0, 1, 2, 3... with maximum limited by sin θ ≤ 1
Exam Tips
Always convert lines/mm to slit spacing in metres first
Remember n_max is the INTEGER part of d/λ
For white light, red diffracts most (longest λ)
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