Rounding, Estimation & Error Intervals
SPEC N13, N14, N15 · NUMBER
Decimal places · Significant figures · Truncation
1 s.f. estimation · Error intervals from rounding and truncation
Key Definitions
DECIMAL PLACES
The number of digits after the decimal point.
3.147 has 3 d.p.
SIGNIFICANT FIGURES
The digits contributing to precision, counted from the first non-zero digit.
0.00284 has 3 s.f. (2, 8, 4).
TRUNCATION
Cutting off digits after a target position without rounding.
3.789 truncated to 1 d.p. = 3.7 (not 3.8).
ERROR INTERVAL
The range of possible values of a rounded/truncated quantity, written as a ≤ x < b.
High-priority topic
This lesson covers three separate spec points (N13–N15) that appear on every paper. Error intervals in particular have a distinctive inequality format that examiners check strictly.
Rounding to Decimal Places
Look at the NEXT digit → 5 or more: round UP · 4 or less: round DOWN
Example — round 3.148 to 2 d.p.
Target: the 2nd decimal place (the "4").
Next digit: 8. 8 ≥ 5 → round up.
Answer: 3.15
Example — round 0.6273 to 3 d.p.
Target: the 3rd decimal place (the "7").
Next digit: 3. 3 ≤ 4 → round down (keep the same).
Answer: 0.627
⚠️ EXAMINER ALERT — carrying the 9. Rounding 4.2996 to 3 d.p.: the next digit is 6 → round up. But 9 rounded up becomes 10, carrying over: 4.299 + 0.001 = 4.300. Keep the trailing zero — it signals the precision.
Rounding to Significant Figures
Count from the first non-zero digit. Leading zeros are place-holders — they do NOT count as significant.
Example — 402 800 to 2 s.f.
First sig fig: 4. Second sig fig: 0. Next digit: 2 → round down.
Answer: 400 000 (the trailing zeros are place-holders).
Example — 0.04567 to 1 s.f.
First sig fig: 4. Next digit: 5 → round up.
Answer: 0.05
d.p. vs s.f. — the Classic Trap
⚠️ EXAMINER ALERT — counting d.p. instead of s.f.
"Round 0.00284 to 2 s.f." — students write 0.00.
This has zero sig figs (just place-holder zeros).
What to write instead: count from the first non-zero digit. 0.00284 to 2 s.f. = 0.0028.
NumberTo 2 d.p.To 2 s.f.
0.002840.00 ✗0.0028 ✓
0.37860.380.38
45714571 (no decimals)4600
Quick test
Does the question say "decimal places" or "significant figures"? The mark scheme is strict — write the wrong type and lose the mark even if the digits are correct.
Truncation — Different from Rounding
Truncation means cutting off digits after a position without rounding. Whatever comes after the cut is simply discarded.
Truncation never rounds up
3.789 truncated → 3.7 (even though 89 is closer to 8)
5.999 truncated to 1 d.p. → 5.9 (even though 999 is nearly 1 whole)
Why it matters
Calculators often truncate long decimals to fit the display. If you take that as the "true" value, you lose accuracy.
⚠️ EXAMINER ALERT — Nov24 P1 Q16. Truncation is "not regularly tested" and "students struggle with both the required reason and the correct error interval." Learn the distinction from rounding — it is worth revision time.
Estimation — Round to 1 s.f.
Round EVERY value to 1 s.f., then compute
Example
Estimate (19.3 × 4.87) ÷ 0.203
19.3 ≈ 20 | 4.87 ≈ 5 | 0.203 ≈ 0.2
Estimate: (20 × 5) ÷ 0.2 = 100 ÷ 0.2 = 500
Exact value: 19.3 × 4.87 ÷ 0.203 ≈ 463. The estimate 500 is in the right ballpark.
Example
Estimate 197 ÷ 4.9
197 ≈ 200 | 4.9 ≈ 5
Estimate: 200 ÷ 5 = 40
⚠️ EXAMINER ALERT — rounding to more than 1 s.f. Students round 19.3 to 19 and 4.87 to 4.9, then compute "properly." This is NOT an estimation — it is a full calculation with slight rounding. Mark schemes want every value rounded to 1 s.f. before any arithmetic.
Practice Question
Estimate the value of (59.2 × 3.14) ÷ 0.078.
Show your working. 2 marks
M:
Round every value to 1 s.f.
C:
59.2 ≈ 60 | 3.14 ≈ 3 | 0.078 ≈ 0.08
(60 × 3) ÷ 0.08 = 180 ÷ 0.08 = 2250
E:
Estimate ≈ 2250
M1: all values rounded to 1 s.f. A1: correct final answer.
Error Intervals — Rounded Values
A value stated as a rounded number could have come from a range of true values. That range is the error interval.
a ≤ x < b
For a value rounded to the nearest unit u:
Rule for rounding
Half the rounding unit goes each side: LB = stated − u/2, UB = stated + u/2.
The lower bound is included (≤). The upper bound is excluded (<).
MCE Worked Example
A mass m is given as 6.4 kg, correct to 1 d.p.
Write down the error interval for m. 2 marks
M Rounding unit u = 0.1 kg.
Half-unit = 0.05.
LB = 6.4 − 0.05, UB = 6.4 + 0.05.
C Lower bound: 6.35
Upper bound: 6.45
Lower bound included (≤).
Upper bound excluded (<).
E6.35 ≤ m < 6.45
Both inequality signs correct. Both bounds to the right precision (2 d.p.).
Mark scheme
B1 lower bound (6.35 with ≤). B1 upper bound (6.45 with strict <). Both parts needed for 2 marks. Using ≤ at both ends is B1 only.
Strict Inequality at the Top
⚠️ EXAMINER ALERT — using ≤ at both ends.
Students write: 6.35 ≤ m ≤ 6.45
This is wrong. At exactly 6.45, the value would round up to 6.5, not stay at 6.4.
What to write instead: the top must be strictly less than.
6.35 ≤ m < 6.45
Why 6.35 is included
At m = 6.35, the "round half up" convention rounds to 6.4. So 6.35 itself rounds to 6.4 → it is a valid value for m.
Why 6.45 is excluded
At m = 6.45, the convention rounds to 6.5, not 6.4. So 6.45 is NOT a valid value for m → excluded.
Memory device
"LB is in, UB is out." Lower bound included, upper bound excluded. One ≤, one <.
Practice Question
A length L is given as 4.7 m, correct to 1 d.p.
Write down the error interval for L. 2 marks
M:
Rounding unit = 0.1 m. Half-unit = 0.05. LB = 4.7 − 0.05. UB = 4.7 + 0.05.
C:
Lower bound: 4.65 (included). Upper bound: 4.75 (excluded).
E:
4.65 ≤ L < 4.75 ✓
B1 lower; B1 upper with strict <.
Error Intervals — Truncated Values
Truncation discards the digits after the cut — it does NOT split the rounding unit into halves. The range is different from a rounded value.
Truncated to x: x ≤ true value < x + u
where u is the truncation unit.
Why truncation is different
Rounded 3.14 came from any true value in the range 3.135 up to (but not including) 3.145 — values in that range are close enough to 3.14 that rounding lands on 3.14.
Truncated 3.14 came from any true value ≥ 3.14. Anything below 3.14 truncates to 3.13 or lower. Anything from 3.14 up to (but not including) 3.15 truncates to 3.14.
Exam-Style: Nov24 P1 Q16
A value x is truncated to 2 d.p. as 5.28.
Write down the error interval for x. 2 marks
M:
Truncation means anything ≥ 5.28 but < 5.29 would be cut down to 5.28.
C:
Lower bound: 5.28 (included — the value itself truncates to 5.28).
Upper bound: 5.29 (excluded — 5.29 truncates to 5.29, not 5.28).
E:
5.28 ≤ x < 5.29 ✓
Different from rounded case — lower bound is 5.28 itself (not 5.275), upper bound is 5.29 (not 5.285).
Practice Question
Round 0.04972 to 2 significant figures. 1 mark
M:
First non-zero digit is 4 (the "4" in 0.04...). Count 2 sig figs: 4 and 9. Look at next digit (7) → round up.
C:
0.049|72 — the 7 is ≥ 5, so round the 9 up.
9 + 1 = 10, so we carry: 0.049 → 0.050.
E:
0.050 ✓
Keep the trailing zero — it shows the precision (2 s.f.).
Common Errors — Don't Lose These Marks
Students often writeCorrect versionError type
0.00284 to 2 s.f. = 0.000.0028Counted d.p., not s.f.
6.35 ≤ m ≤ 6.456.35 ≤ m < 6.45Upper bound must be strict (<)
Estimated 197 ÷ 4.9 without rounding200 ÷ 5 = 40Must round to 1 s.f. first
Rounded 3.148 to 2 d.p. = 3.143.15Next digit (8) → round up
Truncated 3.14 → interval 3.135 to 3.1453.14 ≤ x < 3.15Truncation not rounding
Summary
Key Points — Lesson 1.10
Rounding rule: next digit ≥ 5 → round up; ≤ 4 → round down.
Sig figs: count from first non-zero digit. 0.00284 to 2 s.f. = 0.0028.
Truncation: cut off digits, never round up. 3.789 truncated to 1 d.p. = 3.7.
Estimation: round EVERY value to 1 s.f., then compute.
Error interval (rounded): LB = stated − u/2, UB = stated + u/2.
Error interval (truncated): LB = stated, UB = stated + u.
Inequality format: a ≤ x < b. Lower in, upper out.
Two most dangerous traps
1. Using ≤ at both ends of an error interval.
2. Counting decimal places when the question asks for significant figures.
Rounded vs truncated interval
Both have width u (the precision unit).
Rounded: symmetric around stated value.
Truncated: all above stated value.
Exam Tip
"Premature approximation" — rounding too early in multi-step questions — costs 1 mark. Keep full precision throughout working, then round only at the final step (unless the question specifically asks for an estimate).
Next: Key Definitions